How difficult is it to detect K40 using LaBr3(Ce)?

Scintillation crystals, PMTs, voltage dividers etc...
James Luck
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Re: How difficult is it to detect K40 using LaBr3(Ce)?

Post by James Luck » 16 Nov 2021, 15:54

Sesselmann wrote:
22 Sep 2021, 10:02
Hi Guys,

I am going to build another 1" LaBr3 detector in a couple of weeks, shall make a point of doing a few tests with it before sending it out to the client.

Steven
How bad is the price for LaBr3 of that size? i know it certainly is not the cheapest of materials, but certainly has its place.
Say compared to a CsI of that size or even a two times larger NaI.


-JLuck
James luck
Chicago Ill, USA.
Hobbyist, primary meter: refurbished GR-135 & Ludlum 9.
Mostly detection than identification.

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GigaBecquerel
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Re: How difficult is it to detect K40 using LaBr3(Ce)?

Post by GigaBecquerel » 16 Nov 2021, 19:36

You can get a 1*1" LaBr at around 1.3k, maybe 1k if you ask nicely.

James Luck
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Re: How difficult is it to detect K40 using LaBr3(Ce)?

Post by James Luck » 16 Nov 2021, 20:44

GigaBecquerel wrote:
16 Nov 2021, 19:36
You can get a 1*1" LaBr at around 1.3k, maybe 1k if you ask nicely.
But Becquerel, if i ask you nicely could i get it for free?
Please, pretty please.

You have enough cool things in your lab, share me one.


jk, that's not a terrible amount i was just looking at prices for individual crystals and came out with that rough amount for myself to build one.

-JLuck
James luck
Chicago Ill, USA.
Hobbyist, primary meter: refurbished GR-135 & Ludlum 9.
Mostly detection than identification.

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GigaBecquerel
Posts: 163
Joined: 04 Jul 2020, 07:34
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Re: How difficult is it to detect K40 using LaBr3(Ce)?

Post by GigaBecquerel » 16 Nov 2021, 22:19

I wish I could sell them for this price!
But no, I meant that's the price from various chinese sellers, like ost, or epic etc.

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