Beta + decay and 511 kev annihilation peak
Posted: 10 Aug 2019, 05:17
Hello all,
I am not a physicist and my question is probably pretty dumb, but I am really puzzled...
When an atom undergoes a beta+ decay, a positron and a neutrino are expelled. The positron then annihilates with an electron, releasing two gamma photons with the characteristic 511 kev energy.
A single gram of potassium with the natural potassium isotope composition has 31Bq of gamma activity from electron capture and about 9 times higher beta activity. Wouldn't that mean that for each 1461 kev gamma event registered by the detector, there should be at least 9 times more 511 kev annihilation events registered? But that definitely doesn't correspond to the K-40 spectrum I get (and also with virtually every K-40 spectra I've seen online). The 511kev photopeak is usually negligible as compared to the 1461 one.
What's the reason for this? Or perhaps I am getting something very wrong...
I am not a physicist and my question is probably pretty dumb, but I am really puzzled...
When an atom undergoes a beta+ decay, a positron and a neutrino are expelled. The positron then annihilates with an electron, releasing two gamma photons with the characteristic 511 kev energy.
A single gram of potassium with the natural potassium isotope composition has 31Bq of gamma activity from electron capture and about 9 times higher beta activity. Wouldn't that mean that for each 1461 kev gamma event registered by the detector, there should be at least 9 times more 511 kev annihilation events registered? But that definitely doesn't correspond to the K-40 spectrum I get (and also with virtually every K-40 spectra I've seen online). The 511kev photopeak is usually negligible as compared to the 1461 one.
What's the reason for this? Or perhaps I am getting something very wrong...